Example · SAS and CPCT
If AB=DE, AC=DF and included angles ∠BAC=∠EDF, then △ABC≅△DEF by SAS with A↔D, B↔E and C↔F. Therefore BC=EF by CPCT.
Class 9 › Mathematics › CBSE topic 9
Understand the idea, practise the reasoning and apply it in an investigation. These original notes follow the regular Class IX Mathematics syllabus; the Advanced course is separate.
Be able to explain the key result, choose a method that fits the question, show reasoning clearly and verify the answer.
Congruent triangles have the same shape and size, so one can be placed over the other to match every corresponding vertex, side, and angle. Record the vertex correspondence in the congruence statement: writing △ABC≅△DEF asserts A↔D, B↔E, and C↔F.
After a valid congruence proof, CPCT says corresponding parts of congruent triangles are equal. Do not use CPCT before establishing congruence. AAA fixes angles and shape but permits different sizes, so it proves similarity, not congruence. SSA is not a general test: two given sides and a non-included angle can fit more than one triangle. A diagram that appears unique is not a proof.
Isosceles triangle result: If AB=AC, compare △ABC with △ACB. The equal sides AB=AC and AC=AB, and the included angle at A is common; SAS gives congruence, so ∠B=∠C by CPCT. The converse is also true: equal base angles imply the opposite sides are equal. Always identify the equal side-angle correspondence.
Rigidity: fixing three side lengths determines a triangle (up to reflection), which is why triangular frames resist changing shape. A four-sided frame with hinged joints can deform unless a diagonal or another brace adds a constraint.
Attempt each calculation before reading the solution.
If AB=DE, AC=DF and included angles ∠BAC=∠EDF, then △ABC≅△DEF by SAS with A↔D, B↔E and C↔F. Therefore BC=EF by CPCT.
Keep a record of materials, steps, observations and conclusion.
Use your prescribed NCERT textbook and teacher’s sequence. These are original study notes, not copied textbook answers.