Worked example 1
Question: If tanθ=3/4 for an acute θ, find sinθ and cosθ.
Solution: Take opposite=3k, adjacent=4k. Hypotenuse=5k by Pythagoras. Therefore sinθ=3/5 and cosθ=4/5.
Define the six trigonometric ratios for an acute angle, use standard angle values, and connect ratios with simple identities.
Define the six trigonometric ratios for an acute angle, use standard angle values, and connect ratios with simple identities.
Relative to angle θ: sine is opposite/hypotenuse, cosine is adjacent/hypotenuse, and tangent is opposite/adjacent. Their reciprocals are cosecant, secant and cotangent. Ratios depend on the angle, not the triangle’s size, because right triangles with the same acute angle are similar.
Memorise sin, cos and tan values for 0°, 30°, 45°, 60° and 90° where defined. Use complementary ratios and reciprocal relationships to simplify expressions.
These are original practice questions modeled on common board-exam patterns; they are not reproduced past-paper questions.
Question: If tanθ=3/4 for an acute θ, find sinθ and cosθ.
Solution: Take opposite=3k, adjacent=4k. Hypotenuse=5k by Pythagoras. Therefore sinθ=3/5 and cosθ=4/5.
Question: Evaluate 2sin30°+cos60°−tan45°.
Solution: 2(1/2)+(1/2)−1=1/2.
Make a 30°–60°–90° triangle from paper, measure its sides, and calculate sin, cos and tan for 30° and 60°. Compare your ratios with the standard table; explain small differences as measurement error.
Record: Write the aim, materials, steps, observations and conclusion in your notebook. Follow teacher supervision for any classroom activity.
Try each question before opening its solution.
Adjacent=√(13²−5²)=12, so cosθ=12/13.
By the identity the value is 1.
tan60°=√3 and cos30°=√3/2.
Aligned to the Class X Mathematics curriculum for 2026–27 and the NCERT Mathematics textbook. Always confirm any school-specific internal assessment with your teacher.